WMIC help

[herrasher at gmail.com (Kennith Asher)]

The problem here appears to be one of interrogating the correct node with
the correct context.

I was hopeful that I could interrogate a domain controller using the /node:
context but that doesn't appear to function as expected either.

I am able to interrogate any system where a user has logged in using the
following context:

wmid /node:"domain" netlogin where (Name like "%username") GET
PasswordExpires

The requirement appears to be that the user must have logged into the
system.

Ken

On Thu, Jun 11, 2009 at 9:42 AM, Michael Douglas <mick at pauldotcom.com>wrote:

> Bah.  This doesn't work... you have to enter the actual user's password.
>
> Sorry for the bum advice!
> - Mick
>
>
>
> On Wed, Jun 10, 2009 at 8:55 PM, Michael Douglas<mick at pauldotcom.com>
> wrote:
> > If you're an admin, you should be able to force the wmic check to
> > happen in the scope of another user.
> >
> > wmic /user:"domain\user" netlogin get passwordexpires
> > (note you'll likely need to keep the quotes in the line above. wmic is
> > very picky about global flag values.)
> >
> > I believe this will work... But I'm not VPNed into my lab at work
> > right now to test and see.  Please let us know if this works as you
> > wanted it to.
> >
> > My answers might be wrong, but they're FAST!   ;-)
> > - Mick
> >
> > On Wed, Jun 10, 2009 at 4:29 PM, Kennith Asher<herrasher at gmail.com>
> wrote:
> > > Hey all you WMIC gurus out there.  I'm trying to find a straightforward
> > > means of identifying when a domain user's password will expire.  Is
> there a
> > > modifier or switch I can set to bring back password expiry for another
> > > domain user?
> > >
> > > I know I can use:
> > >
> > > Wmic netlogin get passwordexpires
> > >
> > > to find when my password expires, can this be done for another domain
> user?
> > > Assume I have admin privileges.
> > >
> > > Oh, and just so that we're clear here, this is for the domain we use at
> > > work, I am doing this on behalf of a user I support.
> > >
> > > Thanks,
> > >
> > > Ken
> > >
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