Re: Why redundant frames?

["George Peaslee" <gpeaslee () verizon net>]

A couple things come to mind.

In your TCP options field of the handshake, what is the Maximum segment 
size?

Is there a device that is setting a smaller MTU in the path such as a 
router? (Path MTU Discovery)


----- Original Message ----- 
From: "Tony Anecito" <adanecito () yahoo com>
To: "Community support list for Wireshark" <wireshark-users () wireshark org>
Sent: Wednesday, October 14, 2009 10:43 AM
Subject: Re: [Wireshark-users] Why redundant frames?


Hi All,

More info. Each frame in wireshark is listed as having 539bytes captured and 
on the wire. My MTU is set to 1500 byte packets so if this is a 
fragmentation of data why would the data be split into two frames when one 
should have at least used two packets within a frame?

Sorry for the questions I am a newbe to this level of analysis.

Many Thanks,
-Tony

--- On Wed, 10/14/09, Tony Anecito <adanecito () yahoo com> wrote:

> From: Tony Anecito <adanecito () yahoo com>
> Subject: [Wireshark-users] Why redundant frames?
> To: "Wireshark Users" <wireshark-users () wireshark org>
> Date: Wednesday, October 14, 2009, 9:03 AM
> Hi All,
>
> I am analyzing some traffic for my app using Wireshark. I
> captured a single request from my app to a web service and
> noticed that there appeared to be a redundancy in two
> frames. I am seeing something called a "TCP segment of a
> reassembled PDU" and then my Post being sent from the source
> (my client app) to the destination (web service). And the
> same sequence coming back from the destination (web service)
> to the source (my client app).
>
> Does anyone know why the TCP segment of a reassembled PDU
> is be sent and then coming back? It looks like it contains
> the same data or payload.
>
> Thanks,
> -Tony
>
>
>
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