Wireshark mailing list archives

Re: getting the time


From: Brian Oleksa <oleksab () darkcornersoftware com>
Date: Thu, 21 Jan 2010 14:25:57 -0500

Guy

It is a pointer into the data that I have constructed based on the data 
in the packet.
There is a lot of packets before these 8 bytes and there is a lot of 
packets after these 8 bytes.

I am controlling where I am at with the prt / offset.

Before I was just skipping this packet because I was not sure how to 
format it. So I was just doing:
                ptr += 8;
                offset += 8;
To skip over these 8 bytes.

But now (as you are aware)...I just want to grab these 8 bytes (which is 
UTC time since the epoc in milliseconds)....and I want to format it into 
some kind of readable date. It doesn't matter the format of the date... 
I just want to be able to read it. (for example: 1-21-2010  15:36.... or 
something like this).

I also have to figure out if I need to swap these bytes or not as well.

Some of the other packets (that are before these bytes and after these 
bytes) I had to swap them first to make sense out of them.

Thanks,
Brian


Guy Harris wrote:
On Jan 21, 2010, at 11:09 AM, Brian Oleksa wrote:

  
It points to the actual byte that I am at (which is the beginning of the 
8 bytes that I need for time).
    

What are those bytes in?  Did you get a pointer to the packet data with tvb_get_ptr(), or is it a pointer into data 
you've constructed based on the data in the packet?
___________________________________________________________________________
Sent via:    Wireshark-dev mailing list <wireshark-dev () wireshark org>
Archives:    http://www.wireshark.org/lists/wireshark-dev
Unsubscribe: https://wireshark.org/mailman/options/wireshark-dev
             mailto:wireshark-dev-request () wireshark org?subject=unsubscribe
  
___________________________________________________________________________
Sent via:    Wireshark-dev mailing list <wireshark-dev () wireshark org>
Archives:    http://www.wireshark.org/lists/wireshark-dev
Unsubscribe: https://wireshark.org/mailman/options/wireshark-dev
             mailto:wireshark-dev-request () wireshark org?subject=unsubscribe


Current thread: