Wireshark mailing list archives

Re: jitter calculation example on wireshark wiki


From: "RUOFF, LARS (LARS)** CTR **" <lars.ruoff () alcatel-lucent com>
Date: Tue, 23 Mar 2010 14:20:14 +0100


 If i run this at centralized place i.e Astersik pbx: will it give some additional information. I mean its hard to 
get end to end jitter but if i run it on centralized server than i can have both sides RTP.so is it possible using 
wireshark to just tell wire shark to calculate the jitter of both sides.

Capturing on a central media point will only give you the incoming jitter on all segments. (Are you sure that RTP 
really goes through your central point? Usually RTP is sent directly between media endpoints.)

But if you assume symmetric conditions, that will give you a good overall picture.

  Can you explaing this line -> network jitter is symmetric ?
With "symmetric" i mean same conditions on direction A-->B as for B-->A.
While this assumption is probably true in most cases for the mean (average) jitter over time, it is probably not true 
for the jitter at a given particular time.
But usually average values is all that you want.

Regards,
Lars
 


________________________________

        From: wireshark-users-bounces () wireshark org [mailto:wireshark-users-bounces () wireshark org] On Behalf Of 
capricorn 80
        Sent: lundi 22 mars 2010 16:27
        To: wireshark-users () wireshark org
        Subject: Re: [Wireshark-users] jitter calculation example on wireshark wiki
        
        


         Hi lars!
        
         Thanks for your reply.
        
         If i run this at centralized place i.e Astersik pbx: will it give some additional information. I mean its hard 
to get end to end jitter but if i run it on centralized server than i can have both sides RTP.so is it possible using 
wireshark to just tell wire shark to calculate the jitter of both sides.
        
          Well right now i am doing is like this that I am running wireshark on both sides so i have RTP of A ---> B 
and  B ---> A. Can I by any mean calculate end to end jitter/delay ?
        
          Can you explaing this line -> network jitter is symmetric ?
        
         Regards,
        
        > From: lars.ruoff () alcatel-lucent com
        > To: wireshark-users () wireshark org
        > Date: Mon, 22 Mar 2010 11:20:42 +0100
        > Subject: Re: [Wireshark-users] jitter calculation example on wireshark wiki
        > 
        > It is done on the receiver side.
        > I.e. if we consider an RTP stream direction A-->B, then we calculate jitter for B. For this we analyse all 
incoming RTP packets to B.
        > 
        > So you need to run Wireshark on the end which recieves the RTP packets.
        > But since RTP conversations are usually both-ways and if you assume that network jitter is symmetric, then 
you can do it on either end.
        > 
        > Hope that answers your question,
        > regards,
        > Lars
        > 
        > ________________________________
        > 
        > From: wireshark-users-bounces () wireshark org [mailto:wireshark-users-bounces () wireshark org] On Behalf Of 
capricorn 80
        > Sent: samedi 20 mars 2010 16:36
        > To: wireshark-users () wireshark org
        > Subject: [Wireshark-users] jitter calculation example on wireshark wiki
        > 
        > 
        > 
        > Hi!
        > 
        > The jitter calculation in aaa.pcap is done on the user side or server side? 
        > 
        > As asterisk pbx uses centralized based approach in which every communication goes from server not like skype. 
Is it possible to calculate jitter by running wireshark on the server?
        > 
        > Regards,
        > 
        > 
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