Re: IPv6 longest representation vs INET6_ADDRSTRLEN

[Gerald Combs <gerald () wireshark org>]

On 5/5/11 6:01 AM, Jakub Zawadzki wrote:
> On Thu, May 05, 2011 at 02:01:06PM +0200, Jakub Zawadzki wrote:
> > IMHO when IPv4-mapping is used the longest address is:
> > ::ffff:255.255.255.255 (22B)
> >
> > Anyone knows inet_ntop(AF_INET6, ..) implementation which can actually use 46 bytes?
>  
> Maybe some inet_ntop() implementation don't generate short addresses? (0000 instead of ::)
> so ipv4 mapped address would be: "0000:0000:0000:0000:0000:0000:255.255.255.255"
>
> I think I'll just copy inet_ntop6() from wsutil/inet_ntop.c to address_to_str.c...

RFC 2553 section 6.6 and MSDN's InetNtop documentation both specify 46
characters, but you'd think that if an implementation was smart enough
to check for v4-mapped addresses it would be smart enough to compress
zeroes.

-- 
Join us for Sharkfest ’11! · Wireshark® Developer and User Conference
Stanford University, June 13-16 · http://sharkfest.wireshark.org
___________________________________________________________________________
Sent via:    Wireshark-dev mailing list <wireshark-dev () wireshark org>
Archives:    http://www.wireshark.org/lists/wireshark-dev
Unsubscribe: https://wireshark.org/mailman/options/wireshark-dev
             mailto:wireshark-dev-request () wireshark org?subject=unsubscribe