Making a Web Request is failing with 403 Request Forbidden

[Vineet Mishra <clearmidoubt () gmail com>]

Hi All,

I am making web server call to a website for Shortening the links, that is
bit.ly but recieving a 403 Request Forbidden.
Although if I use their webpage to short the web link its working good.
Can any body tell me what might be the reason for such a vague behavior.

Here is the code included.

String url = "https://bitly.com/shorten/";;
 StringBuffer response;
try {
URL obj = new URL(url);
 HttpsURLConnection con = (HttpsURLConnection) obj.openConnection();

//add reuqest header
 con.setRequestMethod("POST");
con.setRequestProperty("User-Agent", "Mozilla/5.0 (X11; Linux x86_64)
AppleWebKit/537.22 (KHTML, like Gecko) Ubuntu Chromium/25.0.1364.160
Chrome/25.0.1364.160 Safari/537.22");
 con.setRequestProperty("Accept-Language", "en-US,en;q=0.8");
con.setRequestProperty("Accept",
"text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8");
 con.setRequestProperty("Accept-Charset", "ISO-8859-1,utf-8;q=0.7,*;q=0.3");
con.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
 con.setRequestProperty("Host", "bitly.com");

 String urlParameters = "url=
http://bit.ly/1f3aLrP&ie=utf-8&oe=utf-8&gws_rd=cr&ei=sKlwUvPbN8j-rAf-5IDwAQ&basic_style=1&classic_mode=&rapid_shorten_mode=&_xsrf=a2b71eaf499c4690a77a21d3c87e6302
";

// Send post request
con.setDoOutput(true);
DataOutputStream wr = new DataOutputStream(con.getOutputStream());
 wr.writeBytes(urlParameters);
wr.flush();
wr.close();

int responseCode = con.getResponseCode();
System.out.println("Response Code : " + responseCode);

BufferedReader in = new BufferedReader(
        new InputStreamReader(con.getInputStream()));
 String inputLine;
response = new StringBuffer();

while ((inputLine = in.readLine()) != null) {
 response.append(inputLine);
}
in.close();
 System.out.println(response.toString());
} catch (MalformedURLException e) {
// TODO Auto-generated catch block
 e.printStackTrace();
} catch (ProtocolException e) {
// TODO Auto-generated catch block
 e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
 e.printStackTrace();
}

Hoping for your response.

Thanks!

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