Re: Ubuntu PPAs

[Remy Leone <remy.leone () inria fr>]

Hello,

Is there a ppa for wireshark:HEAD as well? Would it be complicated to add
one?

Thanks

Rémy

Le lun. 27 mars 2017 à 13:10, Anders Broman <anders.broman () ericsson com> a
écrit :

> -----Original Message-----
> From: wireshark-dev-bounces () wireshark org [mailto:
> wireshark-dev-bounces () wireshark org] On Behalf Of Peter Wu
> Sent: den 14 mars 2017 17:33
> To: Bálint Réczey <balint () balintreczey hu>
> Cc: Developer support list for Wireshark <wireshark-dev () wireshark org>
> Subject: Re: [Wireshark-dev] Ubuntu PPAs
>
> On Tue, Mar 14, 2017 at 05:23:02PM +0100, Bálint Réczey wrote:
> > > 2017-03-14 14:28 GMT+01:00 Peter Wu <peter () lekensteyn nl>:
> > > > On Tue, Mar 14, 2017 at 12:29:24AM +0100, Bálint Réczey wrote:
> > > > > Hi,
> > > > >
> > > > > I have created a separate PPA for backported dependencies of
> Wireshark:
> > > > > https://launchpad.net/~wireshark-dev/+archive/ubuntu/wireshark-deps
> > > > >
> > > > > This would help people running internal builds of Wireshark. (Hi
> > > > > Anders, sorry for the delay ;-))
> > > > >
> > > > > I plan removing the dependencies from the wireshark-dev/stable PPA
> > > > > to remove redundancy:
> > > > > https://launchpad.net/~wireshark-dev/+archive/ubuntu/stable
> > > >
> > > > Is it possible to express dependencies between PPAs? Otherwise you
> > > > would run into missing dependency issues I think?
> > >
> > > Yes, I have already set the dependency relation for the PPAs, but I
> > > would like to give them a try before I remove the redundant packages
> > > from wireshark-dev/stable.
> >
> > You can add build dependencies to other PPAs, but will these propagate
> when users add a single archive (e.g. with add-apt-repository
> ppa:wireshark-dev/stable)?
> > The Launchpad help pages and the +edit-dependencies page are not very
> clear on this:
> >
> https://help.launchpad.net/Packaging/PPA/BuildingASourcePackage#Dependencies
>
>
> Would it make sense to add the latest libpcap stable too?
> Regards
> Anders
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